Step-by-step explanation:
since f'(x) = 2f(x) and f(3) has no term of x (so, there must be a constant that eliminates x for x = 3), we get
f(x) = x²/9 × c
c = m×e^n
f(1) = 1/9 × m×e^n = 5
=> m×e^n = 45
f(3) = 9/9 × m×e^n = 45
m = 45
n = 0
