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[tex]Given: AD \parallel BCAD∥BC and AD=CB[/tex]
To Prove: [tex]AB \parallel DCAB∥DC[/tex]
1. [tex]AD \parallel BCAD∥BC , AD=CB[/tex]
Reason: Given
2. AC = AC
Reason: Reflexive Property of Equality
3. [tex]\angle 2 = \angle 3∠2=∠3[/tex]
Reason: If Lines are parallel, then Alternate Interior Angles are Equal).
4. [tex]\Delta ACD \cong \Delta CABΔACD≅ΔCAB[/tex]
Reason: SAS
5. [tex]\angle 1 = \angle 4∠1=∠4[/tex]
Reason: CPCTE
6. [tex]AB \parallel DCAB∥DC[/tex]
Reason: If Alternate Interior Angles are Congruent, then Lines are Parallel.
Answer:
The missing Statements and reasons are given below
Statement >> Reason
4. CB ≅ BC >> reflexive property of congruence
5. ∠ABC ≅ ∠DCB and ∠ACB ≅ ∠DBC >> Alternate interior angles theorem
6. ΔACB ≅ ΔDBC >> ASA congruence
7. AB ≅ DC and AC ≅ DB >> CPCTC