A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.​

Respuesta :

The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

The given parameters:

  • Weight of the block, W = 40 N

The normal reaction on the rough surface due to weight of the block is calculated as follows;

[tex]F_n = 40 \ N[/tex]

The static friction between the block and the plane is calculated as follows;

[tex]F_s = \mu_s F_n[/tex]

where;

  • [tex]\mu_s[/tex] is coefficient of static friction

Thus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

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