Question

What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.



Select one:

a. 10N

b. 100N

c. 200N

d. 98N

Answer 1

The smallest value of the force that will make the block not to slide down is 10 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

• Mass (m) = 8 Kg

• Acceleration due to gravity (g) = 10 m/s²

• Normal reaction (N) =?

N = mg

N = 8 × 10

N = 80 N

Finally, we shall determine the frictional force.

• Coefficient of friction (μ) = 0.4

• Normal reaction (N) = 80 N

• Frictional Force (F) =?

F = μN

F = 0.4 × 80

F = 32 N

Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.

From the options given above, only option A has a force that is lesser than the frictional force.

Therefore, the correct answer to the question is Option A. 10 N

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