Answer:
Use similarity and congruency of triangles to solve this question.
Step 1: Prove that Triangle ABC and Triangle ADE are similar
Angle ABC = Angle ADE (given)
Angle ACB = Angle AED (given)
Thus, Triangle ABC is similar to Triangle ADE (two pairs of corr. angles)
Step 2: Map out the ratios of the sides of the triangles
Since Triangle ABC is similar to Triangle ADE,
[tex]\frac{DE}{BC} = \frac{AD}{AB} = \frac{AE}{AC}[/tex]
[tex]\frac{25}{5} = \frac{AD}{3} = \frac{AE}{4}[/tex] = 5
Hence,
AD (y) = 5×3 = 15
AE (x) = 5×4 = 20
