Question

An object starts from rest with a constant acceleration of 2m/s^2 along a straight line. Find the distance travelled for the interval of 10 s.

Answer 1

Answer:

Distance is 100 m

Step-by-step explanation:

From second equation of motion;

${ \rm{s = ut + \frac{1}{2} {at}^{2} }}$

• s is displacement
• u is initial velocity, u = 0 [ from rest ]
• a is acceleration, a = 2 m/s²
• t is time, t = 10s

${ \rm{s = (0 \times 10) + ( \frac{1}{2} \times 2 \times {10}^{2}) }} \\ \\ { \rm{s = {10}^{2} }} \\ \\ { \rm{s = 100 \: {m} }}$

Answer 2

The distance covered is 200m

Data;

• acceleration = 2m/s^2
• time = 10s
• distance = ?

Distance Covered

To find the distance covered by the object, we have to use the formula

of velocity. But we are not given the velocity or speed of the object here.

$v = s/t$

where s and t are the distance and time respectively.

But from acceleration,

$a = v/t\\v = a*t\\v = 2 * 10 \\v = 20m/s$

The velocity of the object is 20m/s

let's use this to find the distance covered.

$v = s/t\\20 = s/10\\s = 20*10\\s= 200m$

The distance covered is 200m

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