Answer:
Yes. All real numbers are either rational or irrational.
Step-by-step explanation:
The set of all irrational numbers is commonly defined as the set of all real numbers that are not rational.
Let [tex]\mathbb{R}[/tex] denote the set of all real numbers. Let [tex]\mathbb{Q}[/tex] denote the set of all rational numbers.
For any given real number [tex]x[/tex] ([tex]x \in \mathbb{R}[/tex],) either [tex]x\![/tex] is rational ([tex]x \in \mathbb{Q}[/tex]) or [tex]x\!\![/tex] isn't rational ([tex]\lnot (x \in \mathbb{Q})[/tex], such that [tex]x \not\in \mathbb{Q}[/tex] and thus [tex]x \in (\mathbb{R} \backslash \mathbb{Q})[/tex].)
Assume that [tex]x[/tex] isn't a rational number. By the definition of rational numbers, since [tex]x\!\![/tex] is a real number but not a rational number ([tex]x \in (\mathbb{R} \backslash \mathbb{Q})[/tex],) [tex]x\![/tex] would be an irrational number.
Therefore, either [tex]x[/tex] is rational or [tex]x\![/tex] is irrational. Every real number would either be rational or irrational.