The equation of the line perpendicular to y = 8 - 5z is 5x+8y=16.
8y=-5x+16
y=-5/8x+2.
To be perpendicular, the slope has to be 8/5.
The slope-intercept form is y=mx+c
Where m is the slope and c is the y-intercept.
So y=8/5x+b.
We can plug in the given coordinates to get
7=8/5*-5+b
7=-8+b
b=15.
So eqn is y=8/5x+15 or in point-slope form, y=8/5x+15
5y=8x+75
5y-8x=75
The equation of the line perpendicular to y = 8 - 5z is 5x+8y=16.
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