Question

Please help my physics teacher cannot teach pls hurry pls help uwu

Answer 1

Hi there!

To find how much the spring stretches with the mass attached, we must find the spring's equilibrium point.

The equilibrium point satisfies the following:

$\large\boxed{\Sigma F = 0}$

The two forces acting in this situation are the weight of the mass and the spring force.

The spring force (restoring force) is in the opposite direction of the weight, so:

$\Sigma F = 0 = Mg- k\Delta x$

Mg = weight

k = Spring Constant (N/m)

Δx = distance to equilibrium point (m)

Now, we can set the two equal to each other:

$Mg = k\Delta x\\\\544 = 1146\Delta x\\\\\boxed{\Delta x= .475 m}$