1. A hat store tracks the state of college and professional team hats for m, months. The number of
college hats sold is represented by (6m+3). The number of professional hats sold is represented by
(5m-2). Write an expressions to show how many more college hats were sold than professional hats.
Then evaluate the expression if m equals 10.
NYS
2. Which expression is equivalents to the expression -3(4x-2)-
2x ? Explain the process you used to find your solution.
A. -8x
B. -16%
C. -14x-2
D. -14x + 6
3. A square scrapbooking page has a perimeter of (8x+20) inches. What is the length of one side of the
scrapbooking page? Show your work.

Respuesta :

1)  The expression representing how many more college hats were sold than professional hats is [tex]m+5[/tex]

when  [tex]m=10[/tex], [tex]15[/tex] more college hats were sold

2)  The equivalent expression to [tex]-3(4x-2)-2x[/tex] is [tex]-14x+6[/tex]. The explanation is found in the steps below

3) The length of one side of the square scrapbooking page will be

[tex](2x+5)\text{ inches}[/tex]. The working is shown below.

1)    According to the question, [tex]m[/tex] is the number of months hats were sold.

[tex]6m+3[/tex] is the number of college hats sold in [tex]m[/tex] months

[tex]5m-2[/tex] is the number of professional hats sold in [tex]m[/tex] months

Since [tex]6m+3>5m-2[/tex] when [tex]m>0[/tex]

the expression representing how many more college hats were sold than professional hats is

[tex](6m+3)-(5m-2)\\=6m+3-5m+2\\=m+5[/tex]

when the number of months hats were sold is [tex]10[/tex], [tex]m=10[/tex], and

[tex]m+5=(10)+5=15hats[/tex]

[tex]15[/tex] more college hats were sold in [tex]10[/tex] months

2)  To get the equivalent expression to [tex]-3(4x-2)-2x[/tex], carry out the steps below

remove brackets

[tex]-12x+6-2x[/tex]

arrange like terms

[tex]-12x-2x+6[/tex]

simplify like terms

[tex]-14x+6[/tex]

The answer is (D)

3)  Let the length of one side of the square be [tex]s[/tex]

The perimeter will be  

[tex]4s=8x+20[/tex]

making [tex]s[/tex] the subject of the formula

[tex]\dfrac{4s}{4}=\dfrac{8x+20}{4}\\\\s=(2x+5)\text{ inches}[/tex]

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