can I have some help?
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Answer:
[tex]x = \sqrt{58} [/tex]
Step-by-step explanation:
first, you should draw a line to separate the triangle from the rectangle
You can get the height if the triangle by saying 16-9
This will give you 7
The base of the triangle is 3 because the opposite side is given and the opposite sides of a rectangle are equal
Now that we have the measurements of the triangle we can use the Pythagorean theorem
[tex] {c}^{2} = {a}^{2} + {b}^{2} [/tex]
[tex] {x}^{2} = {7}^{2} + {3}^{2} [/tex]
[tex] {x}^{2} = 49+ 9[/tex]
[tex] {x}^{2} = 58[/tex]
[tex]x = \sqrt{58} [/tex]