Respuesta :

Answer:

X = 1

Y = 5

Step-by-step explanation:

we have to figure out what x and y = that make both answers correct

3 x 1 = 3

3 + 5 = 8

That means that the first equation is right with X = 1 and Y = 5

Let's see the second equation

5 x 1 = 5

5 + 5 = 10

That means both equations are right so the answer would be

X = 1 and

Y = 5

Method of Elimination:

Given pair of linear equations are:

3x+y = 8 Eqn(i)

On comparing with a₁x+b₁y+c₁ = 0

Where,

  • a₁ = 3,
  • b₁ = 1, &
  • c₁ = 8

5x+y = 10 Eqn(ii)

On comparing with a₂x+b₂y+c2₂ = 0

Where,

  • a₂ = 5,
  • b₂ = 1, &
  • c₂ = -10

a₁/a₂ = 3/5

b₁/b₂ = 1/1= 1

c₁/c₂ = 8/10=4/5

We have,

a₁/a₂ ≠ b₁/b₂ ≠ c₁/c₂

So, Given pair of linear equations in two variables have a unique solution.

Now,

On Subtracting eqn(ii) from eqn(i) then

3x+y = 8

5x+y = 10

(-)

________

-2x+0 = -2

_________

⇛-2x = -2

⇛2x = 2

⇛x = 2/2

⇛x = 1

On Substituting the value of x in eqn(i) then

⇛3(1)+y = 8

⇛3+y = 8

⇛y = 8-3

⇛y = 5

Therefore , The solution = (1,5)

Additional comment:

  • If a₁x+b₁y+c₁ = 0 and a₂x+b₂y+c₂ = 0 are pair of linear equations in two variables then
  • If a₁/a₂ ≠b₁/b₂ ≠ c₁/c₂ then they are Consistent and independent lines or Intersecting lines and they have a unique solution.
  • If a₁/a₂ = b₁/b₂ = c₁/c₂ then they are Consistent and dependent lines or Coincident lines and they have infinitely number of many solutions.
  • If a₁/a₂ =b₁/b₂ ≠ c₁/c₂ then they are Inconsistent lines or Parallel lines lines and they have no solution.
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