Question

A store sells 4 varieties of donuts. Chocolate and Jelly are two of the varieties sold. How many ways are there to select 14 donuts so that at least 5 Chocolate donuts and at most 4 Jelly donuts are selected

Answer 1

Answer:

1 way.

Step-by-step explanation:

1) 10 Chocolate Donuts and 4 Jelly Donuts

Answer 2

The number of ways to select 14 donuts so that at least 5 chocolate donuts and at most 4 jelly donuts are selected are 3003.

What is permutation and combination ?

"Permutation and combination are the ways to represent a group of objects by selecting them in a set and forming subsets. It defines the various ways to arrange a certain group of data. When we select the data or objects from a certain group, it is said to be permutations, whereas the order in which they are represented is called combination. Both concepts are very important in Mathematics."

Given,

Number of varieties that are sold are 4

So the number of combinations with atleast 5 chocolate donut and most$14C_4=\frac{14!}{4!(14-4)!} + \frac{14!}{5!(14-5)!} \\\\=1001 +2002\\\\=3003$

Hence, the number of ways to select 14 donuts so that at least 5 Chocolate donuts and at most 4 Jelly donuts selected are 3003.

To know more about permutations and combination here

https://brainly.com/question/1216161

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