The sum in terms of p of four consecutive even integers with p been the smallest is 4(p + 3)
Even numbers are numbers that can be divided into two equal groups and they can be easily divisible by 2 without any remainder.
p is the smallest of the four consecutive even integers. This means p come first and it is the first term of the numbers.
Therefore, the 4 consecutive even integers is represented as follows;
p, p + 2, p + 4, p + 6
So the sum is equal to:
sum = p + p + 2 + p + 4 + p + 6
sum = 4p + 12
sum = 4(p + 3)
learn more on even numbers here: https://brainly.com/question/21514478?referrer=searchResults
