Question

An object is projected with speed of 4ms at an angle of 60° to horizontal. Calculate the time of flight of the object. (g=10ms2)​

Answer 1

0.8 seconds

Explanation:

time of flight = 2u/g

u=4m/s

g=10

= 8/10

= 0.8 sec

just a trial...not sure!!!

Answer 2

Given :

∅ = 60⁰

u = 4 m/s

g = 10m/s²

to find :

T = ?

Solution :

as per formula,

$t = \frac{2u \: sin \theta}{g}$

now put the value : $t \: = \frac{2 \times 4 \times sin \: 60}{10}$

as we know $sin60 \: = \frac{ \sqrt{3} }{2}$

therefore,

$t \: = \frac{8 \times \frac{ \sqrt{3} }{2} }{10}$

as we solve this we get,

$t \: = \frac{ 2\sqrt{3} }{5}$

that's t = 0.69 sec

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