Respuesta :

Answer:

[tex]\huge\boxed{\sf 41,\ 43, \ 45}[/tex]

Step-by-step explanation:

Let the three consecutive integers be x, x + 2 and x + 4

So, the given condition is:

x + x + 2 + x + 4 = 129

3x + 6 = 129

Subtract 6 to both sides

3x = 129 - 6

3x = 123

Divide 3 to both sides

x = 123/3

x = 41

So, the integers are:

x = 41

x + 2 = 41 + 2 = 43

x + 4 = 41 + 4 = 45

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807