The number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles
From the question,
We are to determine the number of moles of silver, Ag, that are present in 7.54 × 10²³ atoms of silver
From the formula
[tex]Number\ of\ moles =\frac{Number\ of\ atoms}{Avogadro's\ constant}[/tex]
Avogadro's constant = 6.022 × 10²³ atoms mol⁻¹
and
From the given information
Number of silver atoms = 7.54 × 10²³ atoms
Putting the parameters into the formula, we get
Number of moles of silver present = [tex]\frac{7.54\times 10^{23} }{6.022\times 10^{23}}[/tex]
Number of moles of silver present = 1.2520757 moles
Number of moles of silver present ≅ 1.25 moles
Hence, the number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles
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