Respuesta :
Answer: Any whole number between 0 and 750, including both endpoints.
One example could be 700 additional songs.
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Explanation:
x = number of additional songs, some nonnegative whole number
1 song takes up 0.002 GB, so x of them take up 0.002x GB of memory.
Add on the 0.5 GB already used to get the expression 0.002x+0.5 to represent the total amount of storage taken up. We want this expression to be 2 or smaller.
[tex]0.002x + 0.5 \le 2\\\\0.002x \le 2-0.5\\\\0.002x \le 1.5\\\\x \le 1.5/0.002\\\\x \le 750\\\\[/tex]
This says the most songs we can add are 750.
Because x is the number of songs, it doesn't make sense to have x be negative. This means [tex]x \ge 0[/tex] or [tex]0 \le x[/tex] is the case as well.
Combining [tex]0 \le x[/tex] and [tex]x \le 750[/tex] produces the compound inequality [tex]0 \le x \le 750[/tex]
The number of additional songs is any whole number between 0 and 750, including both endpoints.
The roster notation of this set could look like this: {0, 1, 2, ..., 748,749,750}
The triple dots indicate "keep this pattern going". That way we don't have to fill in all 751 values which would be a tedious process.
So you can add on something like 700 songs because it's between those endpoints mentioned, but cannot add something like 800 songs.
Answer:
0 - 750 additional songs
Step-by-step explanation:
current: 0.5 mb
remaining: 2-0.5=1.5 mb
each song: 0.002 gb
take remainig amount of space: 1.5 mb and divide by how much space each song takes: 0.002 mb to find out how many songs can fit in 1.5 mb of space
work:
(total amount of storage-used amount of storage)/storage per song
(2.0-0.5)/0.002
= 1.5/0.002
= 750 songs
what are the possible number of additional songs?
anything up until 750.