Answer:
See below
Explanation:
V = h*pi*r^2
V = h*pi*6² = h*pi*36
V = h*pi*3² = h*pi*9
36 cm^3 / 9 cm^3
= 4
Therefore, the volume of beaker A is 2² times the volume of beaker B
EDIT
However if beaker A is twice the height of beaker B (let's say A is 4 cm high and B is 2 cm high) then the factor between the resulting volumes would be 8.
V = h*pi*6² = 4*pi*36 = 452 cm^2
V = h*pi*3² = 2*pi*9 = 56 cm^2
452 cm^2 / 56 cm^2
= 8
Therefore, the volume of beaker A is 2³ times the volume of beaker B
