Question

Pls Help semester ends at 11
2. A 2 kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 m tall.


Circle one: KE / GPE / both


Show your work for finding the values of each type of energy the object has:

Answer 1

Answer:  Both

Explanation:

KE can be solve using the formula:

ke = 0.5 mv^2

where m is the mass of the object

v is the velocity

ke = 0.5 ( 2 kg ) ( 5 m/s)^2

ke = 25 J

the GPE can be solved using the formula:

GPE = mgh

where m is the mass

g is the acceleration due to gravity ( 9.81 m/s^2)

h is the height

GPE = ( 4 kg)(9.81 m/s^2)( 40 m)

GPE = 392.4 J

I hope this helps, have a great day!!