Answer:
About 57.60 mL.
Explanation:
We can utilize the dilution equation:
[tex]\displaystyle M_1V_1 = M_2V_2[/tex]
Where M are the molarities of the solutions and V are the volumes of the solutions.
We want to determine the volume of a 2.903 M NaOH solution to mix in order to produce 500.0 mL of a 0.3344 M solution.
Substitute and solve for V₁:
[tex]\displaystyle \begin{aligned} (2.903 \text{ M})V_1 & = (0.3344 \text{ M})(500.0 \text{ mL}) \\ \\ V_1 & = 57.60\text{ mL} \end{aligned}[/tex]
In conclusion, 57.60 mL of a 2.903 M NaOH solution is needed.
