Question

Which statement is true?


Which statement is true?


The equation -x2 + 6x + 9 = 0 has no real solutions


The equation -x2 + 6x - 9 = 0 has one real solution


The equation -x2 + 6x - 9 = 0 has two real solutions


The equation -x2 + 6x + 9 = 0 has three real solutions

Answer 1

Answer:

The equation -x2 + 6x - 9 = 0 has two real solutions.

Step-by-step explanation:

${b}^{2} - 4ac = {6}^{2} - 4( - 1)( - 9) = 0$

The discriminant equals to 0, so the quadratic equation has 1 real solution.