Ernest would be swimming at 3.25 units on week 10
The explicit formula is given as:
[tex]a_n = a_1 + (n - 1) \times d[/tex]
Also, we have the following parameters
[tex]a_1 =1.0[/tex] -- the initial distance
[tex]d =0.25[/tex] --- the difference between concurrent distances
In week 10, the value of n is 10.
Next, substitute 10 for n in the explicit formula [tex]a_n = a_1 + (n - 1) \times d[/tex]
So, we have:
[tex]a_{10} = 1.0 + (10 - 1) \times 0.25[/tex]
Subtract 1 from 10
[tex]a_{10} = 1.0 + 9 \times 0.25[/tex]
Multiply 9 by 0.25
[tex]a_{10} = 1.0 + 2.25[/tex]
Add 1.0 and 2.25
[tex]a_{10} = 3.25[/tex]
Hence, Ernest would be swimming at 3.25 units on week 10
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