Question

Find the least counting number which when divided by five give a remainder of one and divided by 12 gives a remainder of three

Answer 1

Answer:

  51

Step-by-step explanation:

We can consider up to 5 multiples of 12:

  (0·12 +3) ÷ 5 = 0 r 3

  (1·12 +3) ÷ 5 = 3 r 0

  (2·12 +3) ÷ 5 = 5 r 2

  (3·12 +3) ÷ 5 = 7 r 4

  (4·12 +3) ÷ 5 = 10 r 1

The number we're looking for is 51.