Question

find the 74th term of the following arithmetic sequence. 17, 26, 35, 44

Answer 1

Answer:

t74 = 674

Step-by-step explanation:

Givens

n = 74

a = 17

d = 26 - 17 = 9

Formula

tn = a + (n - 1)* d

Solution

tn = 17 + 73 * 9

tn = 17 + 657

tn = 674

Remark: This is an application of the arithmetic formula for the "last" term.

You pretty much have to know to to juggle the parts as this one was done.

Answer 2

$\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}$

Here we have,

• n = 74

• a = 17

• d = 26 - 17 = 9

$\mapsto\tt{t_n = a + (n - 1) \times d} \\ \\ \mapsto\tt{t_n = 17 + (74 - 1) \times 9} \\ \\ \mapsto\tt{t_n = 17 + 73 \times 9} \\ \\ \mapsto\tt{t_n = 17 + 657} \\ \\ \mapsto\tt{t_n = 674}$