contestada

A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal ideal spring with spring constant (force constant) of 2. 0 × 106 n/m. What is the maximum distance the spring compresses?.

Respuesta :

If the car comes to a stop and compresses the spring by a distance x in the process, then the restoring force performs

W = -1/2 (2.0 × 10⁶ N/m) x²

of work on the car. By the work-energy theorem, this is equal to the change in the car's kinetic energy,

∆K = 0 - 1/2 (1500 kg) (25 m/s)²

Solve for x :

-1/2 (2.0 × 10⁶ N/m) x² = -1/2 (1500 kg) (25 m/s)²

x² = (1500 kg) (25 m/s)² / (2.0 × 10⁶ N/m)

x = √((1500 kg) (25 m/s)² / (2.0 × 10⁶ N/m))

x ≈ 0.68 m

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