The mass of the block in the drawing is 10 kg. The coefficient of static friction between the block and the vertical wall is 0. 50. What minimum force f is required to start the block moving up the wall?.

Respuesta :

It depends on the direction of the applied force. Consult the attached free body diagram.

If the block is held in place by a force acting perpendicular to the wall, then the block will never move. So the applied force must be acting at some angle θ between 0° and 90° (with respect to the positive horizontal axis).

By Newton's second law, we have

• net perpendicular force

∑ F (⟂) = F cos(θ) - N = 0

• net parallel force

∑ F (//) = F sin(θ) - f - mg = ma

However, we're interested in the minimum force required to get the block moving. This minimum force would exactly counter the frictional force keeping the block in place, so that

F sin(θ) - f - mg = 0

The magnitude of friction is 0.5 N (that is, half the normal force's magnitude, not 0.5 Newtons). So

F sin(θ) - 0.5 N - mg = 0   ⇒   F sin(θ) - 0.5 F cos(θ) = mg

⇒   F (sin(θ) - 0.5 cos(θ)) = mg

⇒   F = mg/(sin(θ) - 0.5 cos(θ))

(where m = 10 kg and g = 9.8 m/s²)

Ver imagen LammettHash
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