Question

Find an equation of a line through (2,-5), perpendicular to 3y=x-6. Write in function notation. ANSWER FAST PLS

Answer 1

Equation of perpendicular line

$\\ \sf\dashrightarrow 3y=x-6$

$\\ \sf\dashrightarrow y=\dfrac{1}{3}x-2$

Comparing with y=mx+b

• m=1/3

Slope of perpendicular line=-3

Passing through (2,-5)

Equation of line in point slope form

$\\ \sf\dashrightarrow y-y_1=m(x-x_1)$

$\\ \sf\dashrightarrow y+5=-3(x-2)$

$\\ \sf\dashrightarrow y+5=-x+6$

$\\ \sf\dashrightarrow x+y-1=0$