Question

The angles of a pentagon are X, X, X, X and (x + 10), Work out the size of the
Largest angle,

Answer 1

Sum of interior angles of pentagon=540

$\\ \sf\dashrightarrow x+x+x+x+x+10=540$

$\\ \sf\dashrightarrow 5x+10=540$

$\\ \sf\dashrightarrow 5x=540-10$

$\\ \sf\dashrightarrow 5x=530$

$\\ \sf\dashrightarrow x=106$

Largest angle=x+10=106+10=116°