Question

A particle of charge 5 × 10–2 C is taken from a point at a potential of 50V to another point at a potential of 250V. Calculate the work done.

Answer 1

Answer:

10 joules

Explanation:

Voltage= U(Potential energy)/qo

Q0 is the test charge

so,

250-50=w/5*10^-2

since potential energy = work done

w=10 joules