Question

Hello Brainly Community, please help me..
Can anyone solve this equation by factoring?
x²-x-20=0
Math homework..
please help. No spam..

Answer 1

Answer:

$\huge\boxed{\sf Solution\ Set = \{5,-4\}}$

Step-by-step explanation:

Given equation is:

$x^2-x-20=0$

Factoring it by mid-term break method.

+4x × -5x = -20x² (multiplication of side terms)

-5x + 4x = -x (Middle term)

Hence, we can split -x into -5 and +4

$x^2-5x+4x-20=0\\\\x(x-5)+4(x-5)= 0\\\\Take \ (x-5)\ common\\\\(x-5)(x+4)=0$

Either:

x - 5 = 0       OR       x + 4 = 0

x = 5             OR       x = -4

Solution Set = {5,-4}

$\rule[225]{225}{2}$

Hope this helped!

~AH1807

Answer 2

$Hiya!$

I know, this is a late questions.. but, why not. answer it.

Here's a explanation!

$x^2-x-20-0$

Step 1: factor left side of equation:

$(x+4)(x-5)=0$

Step 2: Set the factors equal to 0

$x+4=0$

OR:

$x-5=0$

There's a another answer too.

$x=-4$

OR:

$x=5$

ANSWER:

$x=-4$

OR:

$x=5$

Hopefully, this helps you!!

$Sokka$