Question

Solve for c .
4c-3x=2y-3
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Answer 1

$\bf\huge Question:$

$4c-3x=2y - 3$

We need to find the value of c in the given Equation.

$\bf\huge \: Solution:$

$\sf \longmapsto \: 4c-3x=2y - 3$

$\boxed{\bf Add \: 3x \: to \: both \: sides:}$

$\sf \longmapsto \: 4c - 3x + \red{ 3x} = 2y - 3 + \red{ 3x}$

$\underline{\bf \: \bf On \:Simplification :}$

$\sf \longmapsto \: 4c = 2y - 3 + 3x$

$\sf \longmapsto4c = 3x + 2y - 3$

$\boxed{\bf \: Divide \: both \: side s \: by \: 4 :}$

$\sf \longmapsto \: \dfrac{4c}{ \red4} = \dfrac{3x + 2y - 3}{ \red4}$

$\underline{ \bf \: \bf On \:Simplification :}$

$\sf \longmapsto \: c = \dfrac{3}{4} x + \dfrac{1}{2} y + \dfrac{ - 3}{4}$

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$\underline{\bf \: Henceforth, The \: value \: of \: c \: is :}$

$\boxed{\red{\huge \tt{{c}}= \dfrac{3}{4} x + \dfrac{1}{2} y + \dfrac{ - 3}{4} }}$

Or it can also be rewritten as :

$\boxed{\red{\huge \tt \: c = \dfrac{1}{2} y - \dfrac{3}{4} + \dfrac{3}{4} x}}$