Question

Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflection of the parent function over the x-axis.

Use the sine tool to graph the function.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
PLZ GRAPH IT ON THIS GRAPH THAT I PROVIDED PLZZ HELP ASAP PLZZZ

Answer 1

Answer: The graph is shown below.

Explanation:

The midline is y = -3 and the y intercept is (0,-3). This is point A in the diagram below.

The period is pi units, which means that going from midline to peak (or valley) is 1/4 of this distance. So it's pi*(1/4) = pi/4 = 0.79 units approximately from x = 0 to x = 0.79; which is the x coordinate of point B. Point B is one of the infinitely many maximum points. Notice that the vertical distance from A to B is 4 units, which is the amplitude.

Extra info:

• The equation of this sine curve is y = 4sin(2x)-3
• I used GeoGebra to make the graph