Question

Write an equation of the line that passes through a pair of points:
(-4,-3), (-3, 1)

a. y = 4X – 13
b. y = -4x + 13
c. y = 4x + 13
d. y = 4X -1/13

Please select the best answer from the choices provided

Answer 1

Answer:

y = 4 x + 13

Answer c is correct.

Step-by-step explanation:

We know that,

( -4   -3 ) ⇒ ( x₁   y₁)

(-3     1)  ⇒ ( x₂    y₂)

You can use y = m x + c to find the equation.

Here,

m = slope

c = y- intercept

First, let's find the slope ( m ).

$m =\frac{y_{1}-y_{2} }{x_{1}-x_{2} }$

$m=\frac{-3-1}{-4-(-3)}$

$m=\frac{-4}{-4+3}$

$m=\frac{-4}{-1}$

$m=4$

Now let us find the y intercept.

Let take ( -4, -3 ) coordinate for that.

y = m x + c

-3 = 4 × -4 + c

-3 = -16 + c

-3 + 16 = c

13 = c

And now let's create the equation.

y = m x + c

y = 4 x + 13

Hope this helps you.

Let me know if you have any other questions :-)

Answer 2

Answer:

y=4x+13

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(1-(-3))/(-3-(-4))

m=(1+3)/(-3+4)

m=4/1

m=4

y-y1=m(x-x1)

y-(-3)=4(x-(-4))

y+3=4(x+4)

y=4x+16-3

y=4x+13