Question

please help ×ω×
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Answer 1

Answer:

a² - 7a + 10

Step-by-step explanation:

Substitute all x variables for (2 - a) and evaluate.

$(2-a)^2+3(2-a)\\\\(2-a)(2-a)+3(2-a)\\\\4-2a-2a+a^2+6-3a\\\\a^2-7a+10$

Answer 2

$option \: (b)$

Step-by-step explanation:-

$f(x) = {x}^{2} + 3x$

$put \: x = (2 - a)$

$f(x) = {(2 - a)}^{2} + 3(2 - a)$

Apply (a-b)² formula for (2-a)².

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

$f(x) = {2}^{2} + {a}^{2} - 2(2a) + 3(2 - a)$

$f(x) = 4 + {a}^{2} - 4a + 6 - 3a$

$f(x) = 4 + {a}^{2} - 7a + 6$

$f(x) = {a}^{2} - 7a + 6 + 4$

$f(x) = {a}^{2} - 7a + 10.$

Hence, option (b) is correct.