Answer:
2. n= (.00201 L)(1.205 g *L-1)/29.0 g*mol-1 = 8.352 x10^-5 moles3. R=CP/n =(.00001838)(1)/8.352 x10^-5 =0.22 L*atm/mol K4. R=0.08206 L*atm/mol KResults and discussion:What I learned from today’s lab is how volume and temperature relate to each other when taking the measurements and plotting them in a graph.
Definitely, possible error such as heat from our hands can transfer over to graduated cylinder which could change temperature of water.Questions:1. This experiment deals with the relationship between volume and temperature for a fixed amount of gas at constant pressure. Design an experiment, which would allow you to study the relationship between pressure and temperature for a fixed amount of gas at constant volume. Show a diagram of the apparatus and a plot of P versus T for the data you expect to obtain. Is the relationship between P and T direct or inverse?As the temperature increases the pressure also increases and vice versa.2. In this experiment, air was assumed to be an ideal gas. Does this assumption lead to a significant error? Explain your answer? This assumption would probably not lead to significant error unless the experiment is conducted through a change that would change the gas.3. Show by calculation that the weighted-average “molecular weight” of air is 29.0 g⋅ mol-1.
Explanation:
