Answer:
Sorry for the late answer, but hopefully you still want the question answered:
In order to find the area of the entire figure, you just have to divide them into separate pieces, for example here I can see that I can easily split the entire shape into 2 rectangles and one triangle.
Area of a triangle = (base x height) / 2
Area of a rectangle = length x width
The triangle on the top has a heigh of 8 yds, but the base is still incomplete, we can see that after 15yds, the line stops and immediately makes a long rectangle that has a width of 4yds. Right beside that rectangle, you can also see a line continuing to 8 yds. The triangle's "hypotenuse" (the long slanted side) ends halfway through the 8ds line, as indicated by the 4yd line proceeding immediately after the line intersects.
So the base of the triangle would be 15 + 4 + (8 - 4) = 23 yds
Now just plug in the formula for area of the triangle
A = (b x h)/2 = (23 x 8) / 2
A = 92 yd^2
Now you have the two rectangles left. One of the rectangles has a width of 4 yds and a length of 17 yds. Plug in the formula
A = l x w
A = (17 x 4)
A = 68yd^2
The last rectangle has a width of 5 yds and a length of 8yds, just plug in the formula again for here
A = l x w
A = (8 x 5)
A = 40yd^2
Now just add all the areas of the shapes together
(92) + (68) + (40) = 200 yd^2
The area of the figure is 200 yd^2
I will post a picture of the diagram below (excuse me for my terrible handicraft, not artistically gifted, unfortunately)
