If a clock frequency is applied to a cascaded counter, The lowest output frequency available will be
For a cascade counter,
Overall frequency = [tex]5*8*10*10[/tex]
Overall frequency = [tex]4000[/tex]
Therefore,
the lowest frequency
[tex]F = \frac{10*10^6}{4*10^3}\\\\F = 2500Hz\\\\F = 2.5kHz[/tex]
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