(a) The velocity of the object at maximum height is zero.
(b) The time taken for the object to reach the maximum height is 1.61 s.
(c) The maximum height reached by the object is 12.74 m.
(d) The velocity of the when it reaches its original height is 15.8 m/s.
The given parameters:
- Velocity of the object, v = 15.8 m/s
The time taken for the object to reach the maximum height is calculated as follows;
[tex]v_f = v_0 -gt\\\\0 = 15.8 - 9.8t\\\\9.8t = 15.8\\\\t = \frac{15.8}{9.8} \\\\t = 1.61\ s[/tex]
The maximum height reached by the object is calculated as follows;
[tex]v_f^2 = v_o^2 - 2gh\\\\0 = v_0^2 - 2gh\\\\2gh = v_0^2 \\\\h = \frac{v_0^2 }{2g} \\\\h = \frac{(15.8)^2}{2\times 9.8} \\\\h = 12.74 \ m[/tex]
The velocity of the when it reaches its original height is equal to the initial velocity = 15.8 m/s.
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