Question

An urn contains 15 red balls and 10 blue balls. You select three balls from the urn. What is the probability that you have selected two blue balls and one red ball

Answer 1

Answer:

9/92

Step-by-step explanation:

P(2b,1r) = $\frac{10}{25}$ x $\frac{9}{24}$ x $\frac{15}{23}$ = $\frac{9}{92}$