Answer:
Step-by-step explanation:
I'd like to work with the slope-intercept line format, y=mx+b, where m is the slope and b the y-intercept. To find b, the y-intercept, rearrange this equation to solve for b:
b = y - mx
The given point may be inserted for x and y and b is the result.
But the format presented in the question options is point-slope form.
y − y1 = m(x − x1)
m is the slope and the equation only needs one point, (x1, y1) to complete.
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(-2,1) m = -3
We know the slope is -3, so in slope-intercept form:
y = -3x + b
One can calculate b by the following:
b = y - mx
b = 1 - (-3)*(-2)
b = -5
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But the question is set up to be answered using the point slope form.
y − y1 = m(x − x1)
m is -3:
y − y1 = -3(x − x1)
We are given one point, (-2,1), so enter that for (x1,y1)
y − 1 = -3(x − -2)
y - _1_ = _-3_ ( x - _-2_ ) ?
y-1 = -3x - 6
y = -3x - 5
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(3,-4) m = -1
y = -1x + b
y − y1 = m(x − x1)
y − (-4) = -1(x − 3)
y - _-4_ = _-1_ ( x - _3_ ) ?
y+ 4 =-18(x-3)
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(-2,-4) m = 1
y − y1 = m(x − x1)
y − (-4) = 1(x − (-2))
y - (-4)__ = _1_ ( x - _(-2)_ ) ?
y + 4 = 1(x +2)
y + 4 = (x +2)
y = 1x -2
