Answer:
Squares should measure 2 inches per side ensures maximum box volume
Step-by-step explanation:
[tex](12-2x)^{2} =144-48x+4x^{2}[/tex]
[tex]V=x(144-48x+4x^{2} )=144x-48x^{2} +4x^{3}[/tex]
[tex]V'=144-96x+12x^{2}[/tex] = [tex](x-6)(x-2)[/tex]
[tex]x_{1} =6[/tex]
[tex]x_{2} =2[/tex] this is de right value
Hope this helps