Question

Consider the reaction below. 2C6H14 19O2 Right arrow. 12CO2 14H2O How many moles of hexane (C6H14) must burn to form 18. 4 mol of carbon dioxide? 1. 53 mol 3. 07 mol 110. Mol 175. Mol.

Answer 1

In the reaction given, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.

STOICHIOMETRY:

According to this question, the following balanced equation is given:

2C6H14 + 19O2 → 12CO2 + 14H2O

Based on the above equation, 2 moles of hexane (C6H14) is burnt in oxygen to produce 12 moles of carbon dioxide (CO2).

This means that for 18.4 moles of carbon dioxide to be formed, (18.4 × 2)/12 = 3.07 moles of hexane must burn.

Therefore, 3.07 moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide.

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