Given the general identity tan X = , which equation relating the acute angles, A and C, of a right â†ABC is true? A. Tan A = B. Cos A = C. Sin C = D. Cos A = tan C E. Sin C =.

Respuesta :

The equation [tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex] relating the acute angles, A and C, of the right triangle ABC is true

The general identity is given as:

[tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex]

The acute angles of the right triangles are given as A, and C.

So, we have:

[tex]A + C = 90[/tex]

This also means that:

[tex]\sin(A) = \cos(C)[/tex]

and

[tex]\sin(C) = \cos(A)[/tex]

Substitute A for x in [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex]

[tex]\tan(A) = \frac{\sin(A)}{\cos(A)}[/tex]

Substitute sin(C) for cos(A) in [tex]\tan(A) = \frac{\sin(A)}{\cos(A)}[/tex]

[tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex]

Hence, the equation [tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex] relating the acute angles, A and C, of the right triangle ABC is true

Read more about right triangles at:

https://brainly.com/question/2437195

Answer:

I took the test on plato and it was correct, it option A

Step-by-step explanation:

A. tan A = [tex]\frac{sin A}{sin C}[/tex]

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