Respuesta :
The equation [tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex] relating the acute angles, A and C, of the right triangle ABC is true
The general identity is given as:
[tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex]
The acute angles of the right triangles are given as A, and C.
So, we have:
[tex]A + C = 90[/tex]
This also means that:
[tex]\sin(A) = \cos(C)[/tex]
and
[tex]\sin(C) = \cos(A)[/tex]
Substitute A for x in [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex]
[tex]\tan(A) = \frac{\sin(A)}{\cos(A)}[/tex]
Substitute sin(C) for cos(A) in [tex]\tan(A) = \frac{\sin(A)}{\cos(A)}[/tex]
[tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex]
Hence, the equation [tex]\tan(A) = \frac{\sin(A)}{\sin(C)}[/tex] relating the acute angles, A and C, of the right triangle ABC is true
Read more about right triangles at:
https://brainly.com/question/2437195
Answer:
I took the test on plato and it was correct, it option A
Step-by-step explanation:
A. tan A = [tex]\frac{sin A}{sin C}[/tex]