Question

A computer's hard disk holds 7. 5 Ă— 107 bytes of information. Jaden adds an extra memory stick so he can store a total of 7. 75 Ă— 107 bytes of information. The memory stick holds m Ă— 10n bytes of information, where m is and n is.

Answer 1

The values of m and n are 2.5 and 6, respectively

The size of the computer hard disk is given as:

$a = 7.5 \times 10^7$

The size after adding the extra memory stick is given as:

$b = 7.75 \times 10^7$

The size (s) of the memory stick is calculated by subtracting the size of the computer hard disk before and after adding the memory stick.

This is represented as:

$s =b -a$

So, we have:

$s =7.75 \times 10^7 -7.5 \times 10^7$

Factor out 10^7

$s =(7.75 -7.5 )\times 10^7$

Subtract 7.5 from 7.75

$s =0.25\times 10^7$

Rewrite as:

$s =2.5\times 10^6$

From the question, we have:

$s =m\times 10^n$

So, the equation becomes

$m\times 10^n = 2.5\times 10^6$

By comparison:

$m =2.5$

$n = 6$

Hence, the values of m and n are 2.5 and 6, respectively

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