Question

The chemical equation below shows the combustion of methane (CH4). CH4 2O2 Right arrow. CO2 2H2O The molar mass of oxygen gas (O2) is 32. 00 g/mol. The molar mass of carbon dioxide (CO2) is 44. 01 g/mol. What mass of CO2, in grams, will form when 8. 94 g O2 completely react? 3. 25 6. 15 13. 0 53. 0.

Answer 1

Answer:

Ans: 6.174g

Explanation:

Consider the Balanced chemical equation

$CH_{4} + 2O_{2}$ → $CO_{2} +2H_{2} O$

since we 8.94g of Oxygen that reacted, we can find the number of moles of oxygen that were involved in the reaction by saying

$n(O) =\frac{m}{mm} \\\\\\n(O) = \frac{8.94g}{32.00g/mol} \\\\n(O) = 0.28mol$

hence the number of moles of oxygen that reacted are 0.28mol

now to find the number of moles of carbon dioxide produced, we relate the mole ratio from the balanced chemical equation

where 2mol of $O_{2}$ produced 1mol of $CO_{2}$

2mol $O_{2}$ : 1mol $CO_{2}$

0.28mol : $X$

∴ 0.14mol of $CO_{2}$ was produced

$n(CO_{2} ) = \frac{m(CO_{2}) }{mm(CO_{2}) }\\\\0.14mol = \frac{m(CO_{2}) }{44.1g/mol}$

$m(CO_{2}) = 6.17g$