The chemical equation below shows the combustion of methane (CH4). CH4 2O2 Right arrow. CO2 2H2O The molar mass of oxygen gas (O2) is 32. 00 g/mol. The molar mass of carbon dioxide (CO2) is 44. 01 g/mol. What mass of CO2, in grams, will form when 8. 94 g O2 completely react? 3. 25 6. 15 13. 0 53. 0.

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The mass of CO2 that will be formed when 8.94 g O2 completely reacts would be 6.15 g

From the equation:

[tex]CH_4 + 2O_2 ---> CO_2 + 2H_2O[/tex]

The mole ratio of O2 to CO2 is 2:1.

Mole of 8.94 g O2 = mass/molar mass

                               = 8.94/32

                                 = 0.28 moles

Equivalent mole of CO2 = 0.28/2

                                         = 0.14 moles

Mass of 0.14 moles CO2 = 0.14 x 44.01

                                          = 6.15 g

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886?referrer=searchResults

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