A coach chooses six out of eight players to go to a skills workshop. If order does not matter, in how many ways can he choose the players for the workshop? 6 8 28 56.

Respuesta :

There are 28 ways to choose the players for the workshop,

A combination in mathematics is the act of choosing elements from a set that includes distinctive members so that the order of selection is not significant or unimportant.

It can be expressed by using the formula:

[tex]\mathbf{^nC_r = \dfrac{n!}{r!(n-r)!}}[/tex]

From the given parameters:

  • Number of players to go to a skills workshop n = 8
  • Number of players a coach chooses  r = 6

[tex]\mathbf{^8C_6 = \dfrac{8!}{6!(8-6)!}}[/tex]

[tex]\mathbf{\implies \dfrac{8 \times 7 \times 6!}{6!(2)!}}[/tex]

[tex]\mathbf{\implies \dfrac{8 \times 7}{2!}}[/tex]

[tex]\mathbf{\implies \dfrac{8 \times 7}{2\times 1}}[/tex]

= 28 ways

Learn more about Combination in mathematics here:

https://brainly.com/question/9465501

Answer:

The answer above is correct! The answer is 28 :)

Step-by-step explanation:

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