Question

Consider the balanced equation. PCl3 3H2O Right arrow. H3PO3 3HCl What is the percent yield of HCl if 42. 0 g of HCl are produced from the reaction of 62. 0 g of PCl3? Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100. 28. 4% 72. 8% 85. 0% 93. 5%.

Answer 1

The percent yield of HCl would be 85%.

From the equation:

$PCl_3 + 3H_2O ---> H_3PO_3 + 3HCl$

The mole ratio of PCl3 and HCl is 1:3.

Mole of 62 g PCl3 = mass/molar mass

                               = 62/137.33

                                = 0.45 moles

Equivalent mole of HCl = 0.45 x 3

                                        = 1.35 moles

Mass of 1.35 moles HCl = 1.35 x 36.5

                                      = 49.44 g

Percent yield = actual yield/theoretical yield x 100

                     = 42/49.44 x 100

                    = 84.95%

More on percent yield can be found here: https://brainly.com/question/2506978?referrer=searchResults