Question

A flask containing neon gas is connected to an open-ended mercury manometer. The open end is exposed to the atmosphere, where the barometric pressure is 734. torr. The mercury level in the open arm is 3.9 cm above that in the arm connected to the flask of neon. What is the neon pressure, in torr

Answer 1

The pressure of the neon gas in torr is 772.98 torr.

Let P = pressure of neon gas, P₀ = atmospheric pressure = 734 torr and h = height of mercury level in open arm = 3.9 cm

Now, since the height of the mercury in the open arm of the open-ended mercury mamometer is higher than that in the neon arm, it implies that the neon pressure is greater than the atmospheric pressure.

So, P = P₀ + ρgh where

• P and P₀ are as given above  
• ρ = density of mercury = 13600 kg/m³,
• g = acceleration due to gravity = 9.8 m/s²
• h = height of mercury in open arm = 3.9 cm = 0.039 m

So, substituting the values of the variables into the equation, we have

P = P₀ + ρgh

P = 734 torr + 13600 kg/m³ × 9.8 m/s² × 0.039 cm

P = 734 torr + 5197.92 Pa

P = 734 torr + 5197.92 Pa × 0.0075 torr/1 Pa

P = 772.9844 torr

P ≅ 772.98 torr

So, the pressure of the neon gas in torr is 772.98 torr.

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